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OCR H446 1.4.1 Data representation consolidation

Part 10 of 11 · H446 1.4.1 · Data types

No new content is introduced here: this is the consolidation piece that pulls the whole of H446 1.4.1 together. A live-event system mixing bookings, lighting values, signed sensor readings, audio, permission flags and messages means the questions never say which method to use, so students have to route to it themselves, starting from closed-book retrieval.

Students will:

  • select the right representation method when the question does not name it
  • move between denary, 8-bit binary and hexadecimal in a mixed conversion table
  • interpret signed readings and complete fixed-width additions with the carry working shown
  • normalise and add values in the OCR floating-point format
  • read a shift or mask operation and state both the result and its purpose

Inside: 4 explanation cells, 1 multiple-choice question, 1 fill-in-the-blanks cell, 2 written answers and 6 number answers. 42 marks, about 55 to 70 minutes.

Series: H446 1.4.1 · Data types, part 10 of 11.

Shared by Coding PathwayVerified teacher

  • 14 cells
  • About 60 minutes
  • CC BY-SA 4.0
  • Shared 31 Aug 2026
  • Updated 3 Sept 2026

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The whole resource, exactly as a class sees it. Answers and marking are held back.

Data representation consolidation

Complete the sections in order, beginning with closed-book retrieval and then applying the ideas in the integrated contexts. No new required knowledge is introduced.

A live-event system combines bookings, lighting values, signed sensors, audio, flags and message characters. No new content is introduced.

Retrieval strategy

Before calculating, label the demand: type choice; base conversion; signed interpretation; arithmetic/overflow; floating point; shift/mask; or character mapping. Then write the relevant representation and width. This two-step diagnosis prevents applying a familiar method to the wrong encoding.

Start with the worked routing examples below, then complete the mixed tasks without topic headings.

Stopping point: complete through binary arithmetic in one lesson. Resume with floating point, shifts, masks and character sets in a second lesson or independent study period.

Worked routing examples

  • '0074' used as an identifier → String: purpose decides the type.
  • 11110000 stated as two’s complement → signed place values, not unsigned conversion.
  • mantissa/exponent pair → interpret both fields before arithmetic.
  • value AND mask → calculate result, then state selected-bit purpose.

Guided confidence check

For each question, write a two-word method label before working. Identify the required method before continuing.

Multiple choice1 mark

The value '0074' is a fixed-format ticket identifier and is never used in arithmetic. Which type is most suitable?

  • AString
  • BInteger
  • CReal
  • DBoolean
Number systems10 marks

Complete the mixed denary, 8-bit binary and hexadecimal conversion table.

a)Binary 01000010. Fill in the denary and hexadecimal.

Binary
0100
0010
DenaryNot answered
Hexadecimal

b)Hexadecimal 03. Fill in the denary and binary.

Hexadecimal
0
3
DenaryNot answered
Binary

c)Denary 20. Fill in the binary and hexadecimal.

Denary
20
Binary
Hexadecimal

d)Denary 58. Fill in the binary and hexadecimal.

Denary
58
Binary
Hexadecimal

e)Denary 97. Fill in the binary and hexadecimal.

Denary
97
Binary
Hexadecimal
Number systems3 marks

Interpret each 8-bit two's-complement sensor change in denary.

a)What is the denary value of the two's complement number 11010010?

Binary
11010010
DenaryNot answered

b)What is the denary value of the two's complement number 11011101?

Binary
11011101
DenaryNot answered

c)What is the denary value of the two's complement number 11011110?

Binary
11011110
DenaryNot answered
Number systems3 marks

Add each pair of 8-bit values and retain the carry working.

a)Add these 8-bit binary numbers: 00001101 + 00010011.

Carries
First number
00001101
Second number
00010011
Total

b)Add these 8-bit binary numbers: 01001000 + 11111101.

Carries
First number
01001000
Second number
11111101
Total

c)Add these 8-bit binary numbers: 10111101 + 10101011.

Carries
First number
10111101
Second number
10101011
Total
Number systems6 marks

Normalise each audio value using a 6-bit mantissa and 4-bit exponent.

a)Normalise the floating point number with mantissa 001111 and exponent 0011.

Start from
001111
Mantissa
0011
Exponent
Normalised
Mantissa
Exponent

b)Normalise the floating point number with mantissa 110001 and exponent 0011.

Start from
110001
Mantissa
0011
Exponent
Normalised
Mantissa
Exponent

c)Normalise the floating point number with mantissa 001110 and exponent 0011.

Start from
001110
Mantissa
0011
Exponent
Normalised
Mantissa
Exponent
Number systems4 marks

Add one pair of OCR-format floating-point audio adjustments. Show alignment, mantissa arithmetic and the normalised result.

Add the floating point numbers 010111 (exponent 0001) and 010000 (exponent 0000). Give a normalised answer.

First number
010111
Mantissa
0001
Exponent
Second number
010000
Mantissa
0000
Exponent
Align
Add mantissas
Total
Mantissa
Exponent
Number systems6 marks

Identify the logical shift direction and number of places in each transformation.

a)10000010 became 00010000. Which shift was applied, and by how many places?

Before
10000010
After
00010000
DirectionNot answered
PlacesNot answered

b)10011010 became 00010011. Which shift was applied, and by how many places?

Before
10011010
After
00010011
DirectionNot answered
PlacesNot answered

c)10010010 became 01001000. Which shift was applied, and by how many places?

Before
10010010
After
01001000
DirectionNot answered
PlacesNot answered
Written answer3 marks

A permissions byte is 11001010 and the system applies OR with 00000101. Give the resulting byte and explain what the mask does.

Separate the bitwise result from the purpose.

Students type their answer here.

Written answer2 marks

The event app expands from English-only notices to messages using many writing systems and emoji. Recommend a character-set approach and justify it.

State a suitable standard and connect its repertoire to the scenario.

Students type their answer here.

Final closed-book checkpoint

Complete each sentence from memory. There is no answer bank and correctness is held for teacher review.

Fill in the blanks4 marks
A negative integer with one zero representation normally uses completion 1. A floating-point mantissa whose first two bits differ is completion 2. A bitwise completion 3 selects which bits an operation affects. A worldwide text repertoire is provided by completion 4.

Closed-book review

Choose one completed example from each family and explain the method without looking back.